4x^2+26x=10.3125

Solution for 4x^2+26x=10.3125 equation:

4x^2+26x=10.3125

We move all terms to the left:

4x^2+26x-(10.3125)=0

We add all the numbers together, and all the variables

4x^2+26x-10.3125=0

a = 4; b = 26; c = -10.3125;
Δ = b2-4ac
Δ = 262-4·4·(-10.3125)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-29}{2*4}=\frac{-55}{8}
=-6+7/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+29}{2*4}=\frac{3}{8}
=3/8
$